What is the pH of a solution if [OH–] = 2.3 x 10–5 M?
i know to use the formula pOH= -log(OH-].....to find the answer but, i don't know how to plug it in my calculator to get the final answer....can someone please explain it to me...thanks for your help!
i know to use the formula pOH= -log(OH-].....to find the answer but, i don't know how to plug it in my calculator to get the final answer....can someone please explain it to me...thanks for your help!
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Don't forget to use
pOH ≈ 14 − pH
to find the pH once you have pOH
Type in 0.000023
Hit log, then =
(Note this is log base 10 so if you have a ln button and a log button, use the log not the ln)
Then find the +/- button to change the sign.
(then subtract the answer from 14 to get pH, so)
Hit M+
cancel
type 14
hit -
press MR
then =
pOH ≈ 14 − pH
to find the pH once you have pOH
Type in 0.000023
Hit log, then =
(Note this is log base 10 so if you have a ln button and a log button, use the log not the ln)
Then find the +/- button to change the sign.
(then subtract the answer from 14 to get pH, so)
Hit M+
cancel
type 14
hit -
press MR
then =