SIMPLE CHEMISTRY PROBLEM—10 pts.
Favorites|Homepage
Subscriptions | sitemap
HOME > > SIMPLE CHEMISTRY PROBLEM—10 pts.

SIMPLE CHEMISTRY PROBLEM—10 pts.

[From: ] [author: ] [Date: 12-02-16] [Hit: ]
35*10^-3) mol/L = 0.567 M-Thats so easy.. are you retarded or something?......
Problem:

A student titrates an unknown solution of H2SO4 with a standard solution of NaOH. The following data are obtained:
Initial reading of acid burette: 0.15 mL
Initial reading if base burette: 1.05 mL
Final reading of acid burette: 22.25 mL
Final reading of base burette: 46.50 mL
Concentration of standard base solution: 0.558 M

Calculate the concentration of the unknown acid solution. Hint: Think carefully about the equation for the reaction before you do the calculations.

-
H2SO4 + 2NaOH ----> Na2SO4 + 2H2O

moles of base = 0.558*(46.5 - 1.05)*10^-3 = 0.02536 mol

It takes 2 moles of base to neutralize 1 mole of acid, so

moles of acid = ½ moles of base = 0.01268 mol

This no of moles was in (22.5 - 0.15)*10^-3 L or 22.35*10^-3 L of acid

Acid concentration = 0.01268/(22.35*10^-3) mol/L = 0.567 M

-
That's so easy.. are you retarded or something?
1
keywords: PROBLEM,pts,SIMPLE,mdash,10,CHEMISTRY,SIMPLE CHEMISTRY PROBLEM—10 pts.
New
Hot
© 2008-2010 http://www.science-mathematics.com . Program by zplan cms. Theme by wukong .