A current of 76.1 mA exists in a metal wire.
How many electrons flow past a given crosssection of the wire in 9.79 min?
Answer in units of electrons
How many electrons flow past a given crosssection of the wire in 9.79 min?
Answer in units of electrons
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number of electrons n = i t / e = 76.1x10^-3 x 9.79 x60 / 1.6 x10^-19 = 4.47x10^22
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There are 1000 (mA) in an amp.
One electron is equal to one Coulomb.(+flow)
Therefore the charge of an electron is 1.6 x10^-19 so the number of electrons in one coulomb is 1/1.6x10^-19
=6.25x10^18 electrons
so for one Amp that would be 6.25x10^18 electrons per second flowing around the circuit/component
Now do the math.... :-)
One electron is equal to one Coulomb.(+flow)
Therefore the charge of an electron is 1.6 x10^-19 so the number of electrons in one coulomb is 1/1.6x10^-19
=6.25x10^18 electrons
so for one Amp that would be 6.25x10^18 electrons per second flowing around the circuit/component
Now do the math.... :-)