Math question????????????

the product of two consecutive positive odd integers in 195. find the integers.
Working out and explanation please!

assume one of the numbers is x, so therefore the other number must be (x+2) since they both have to be odd, other we would use x+1

so the product of these 2 numbers give 195

therefore
(x)(x+2) = 195

expand it
x^2 +2x = 195

move the 195 to the other side and change sign
x^2 +2x -195 = 0

factor this equation to get
(x-13)(x+15) = 0

equate each term with 0
(x-13) = 0
x= 13

(x+15) = 0
x=-15

we can't use -15 since they have to be positive! so the answer is 13, and obviously the next odd number is 15.
and to check 13 times 15 is in fact 195

Let the integer be x
Then 2 consecutive odd integers be x and x + 2

So x ( x+2) = 195
x^2 + 2x - 195 = 0
(x + 15)(x - 13) = 0
So x = -15 and 13 but as x is positive, x = 13

The 2 consecutive positive odd integers are 13 and 15

x( x+2) = 195

x^2 + 2x -195 = 0

( x + 15) ( x-13) = 0

x = 13

ANSWER 13 and 15

The two numbers would be close to the square root of 195, and one of them would be a multiple of 5.