Physics question involving convex mirror? Please help! 10 points.
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Physics question involving convex mirror? Please help! 10 points.

[From: ] [author: ] [Date: 12-02-14] [Hit: ]
well, uh, the focal length is 6cm and the principal axis is 12cm... the objects height is 4 cm.......
My physics teacher didn't really make the homework clear at all :/
So it's asking me to find the position, the height and nature... well, uh, the focal length is 6cm and the principal axis is 12cm... the object's height is 4 cm.. and I don't really get what it is trying to ask me, but like I said, it's asking me to find out the position, height and nature?? Of an image I think? I'm really not sure..

If anyone can help solve this, I will reward ten points. Thanks

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It is difficult to figure out the meaning of " principle axis = 12 cm" here.
But as we have to probably find out the position of image, called v, 12 cm must be u(position of object)
and one cannot find position of image only from f (focal length).
Mirror formula: 1/v + 1/u = 1/f
1/v = 1/f -1/u
= 1/6 - 1/(-12) ...........u is negative as object is placed on left side
=1/4
v= + 4cm ..........(position is positive means image is on right side)
Also, height of image/height of object = h2/h1 = -v/u
Here, h1 = 4cm
h2 = -v(h1)/u
= (-1)(4)(4)/(-12)
= + 1.34 cm
As h2 is positive, the image is erect and virtual
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