A length of wood is to be used to brace a rectangular wall.
If the wall measures 5 metres by 8 metres, find the length
of the brace, to the nearest millimeter.
Does anyone know how to explain this using pythagoras theorem eg.) (h2=a2+b2)??
If the wall measures 5 metres by 8 metres, find the length
of the brace, to the nearest millimeter.
Does anyone know how to explain this using pythagoras theorem eg.) (h2=a2+b2)??
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the pythagorean theorem says that the square of the length of two sides of a triangle (a2+b2) equals the square of the longest side of the triangle.
when a piece of wood is put against a wall, it forms a triangle. This means 5 and 8 are the two smaller sides of the triangle. square 5 and 8 and add them together. 25+64 = 89
now we have the longest side length squared. to find the actual length, square root it to get around 9.434 metres as the length of the wood
when a piece of wood is put against a wall, it forms a triangle. This means 5 and 8 are the two smaller sides of the triangle. square 5 and 8 and add them together. 25+64 = 89
now we have the longest side length squared. to find the actual length, square root it to get around 9.434 metres as the length of the wood
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Assuming the "brace" is the hypotenuse, and makes a triangle with the 5m and 8m lengths.
You use the Pythagorean Theorem as so:
h^2=a^2 + b^2
h=sqrt(a^2 + b^2)
h=sqrt(5^2 + 8^2)
h=sqrt(25+64)
h=sqrt(89)m
You use the Pythagorean Theorem as so:
h^2=a^2 + b^2
h=sqrt(a^2 + b^2)
h=sqrt(5^2 + 8^2)
h=sqrt(25+64)
h=sqrt(89)m
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If the brace is to stiffen the board it wll lie cornor to cornor across the board.
The edge of the board are the legs of a right angled triangle and the brace is the hypotenuse.
To find the length apply Pythagoras' formula
sqrt((5^2) + (8^2)) = 9.434
The edge of the board are the legs of a right angled triangle and the brace is the hypotenuse.
To find the length apply Pythagoras' formula
sqrt((5^2) + (8^2)) = 9.434
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the answer is false