This question is for a lab. In the synthesis of Magnesium oxide, why is the mass of Ammonia discounted when considering the mass of the final product?
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Probably because the ammonia will be the excess reactant, and if so its mass/mol amount will be irrelevant for calculating the mass/mol amount of magnesium oxide.
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If you did it correctly, The Mg3N2 that was made in the crucible by burning Mg in air is mixed with water and heated so that the NH3 that is made is driven off and the reaction looks like this Mg+O2----> 2MgO