A man travels by a car for 3 days. He travelled 10 hours each day. He drove on the first day at 45 km/hr, second day at 40 km/hr and third day at 20 km/hr.pls explain in detail with step
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YOU HAVE NOT MENTIONED WHAT YOU WANT .
10 X 45 = 450 km
10 X 40 = 400 km
10 X 20 = 200 km
Total = 1050 km
Average per day = 1050 /3 = 350 km per day
Average speed = 1050 /30 = 35 km per hour
10 X 45 = 450 km
10 X 40 = 400 km
10 X 20 = 200 km
Total = 1050 km
Average per day = 1050 /3 = 350 km per day
Average speed = 1050 /30 = 35 km per hour
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where is the question ?
still
first day travells 10 hours at 45 km/hr so
10*45= 450 km
2 nd day
10*40=400
3rd day
10*20=200
total 1050 km
travells for total 30 hours
still
first day travells 10 hours at 45 km/hr so
10*45= 450 km
2 nd day
10*40=400
3rd day
10*20=200
total 1050 km
travells for total 30 hours
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He travelled 1,150 km, if that's what you mean.
(45x10)+(40x10)+(20x10)=x
450+400+200=x
There's really nothing to explain.
(45x10)+(40x10)+(20x10)=x
450+400+200=x
There's really nothing to explain.
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All i can understand is the speed of the car everyday.. But where is the exact question of the problem? What will I explain from that problem?
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Rajankar is right
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Sique is right
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That was the 1 question I got wrong on my engineers entry exam...wish I knew