Empirical Formula need help, please

I need to find the Empirical Formula of a compound that's 168.11g/mol.

The compound is made out of:
Carbon- 14.29g
Hydrogen- 0.8g
Oxygen- 12.69g
Nitrogen- 5.56g

If you please tell me how to get the empirical formula for this I would highly appreciate it. You don't necessarily have to do it.
Thanks.

Convert all the masses into moles:

Carbon- 14.29g / 12.0 g/mol = 1.19
Hydrogen- 0.8g / 1.0 g/mol = 0.8
Oxygen- 12.69g / 16.0 g/mol = 0.793125
Nitrogen- 5.56g / 14.0 g/mol = 0.397

Divide by the smallest value:

Carbon- 1.19 / 0.397 = 3
Hydrogen- 0.8 / 0.397 = 2
Oxygen- 0.793125 / 0.397 = 2
Nitrogen- 0.397 / 0.397 = 1

C3H2NO2

You did not mention needing the molecular formula.

168 / 84 = 2

The 84 comes from the weight of the empirical formula, C3H2NO2

The molecular formula is C6H4N2O4