Kinetic and Potential Energy Help (Physics)
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Kinetic and Potential Energy Help (Physics)

[From: ] [author: ] [Date: 12-02-16] [Hit: ]
Eg = mgh= (56 kg)(9.8 N/kg)(34 m)= 18659.Please show step by step.KE = 1/2mV² = (0.at the crest of a hill that is supposedly 34 m above ground level.when skier is 34 m above ground.......
A girl who weighs 56 kg is skiing at a mountain. She is moving @ 16m/s across the crest of a ski hill located 34 m above the ground level at the end of the run.

a) Determine her potential energy relative to the height of the ground at the end of the run.
answer = 10 000 J

I don't know how to get that answer and I need your help!!!

What I tried to do:

Eg = mgh
= (56 kg)(9.8 N/kg)(34 m)
= 18659.2 J

I don't know what I'm doing wrong xD

Please show step by step.

Thank you in advance (will award best answer)

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U have the diagram and we don't :>)

The skier U describe has:
KE = 1/2mV² = (0.5)(56)(16)² = 7168 J
at the crest of a hill that is supposedly 34 m above ground level.
but
U correctly compute the GPE (gravitational potential energy) = mgh = 18659 J
when skier is 34 m above ground...so the GPE of 10,000 J would be at a lower height.

If I suppose that the GPE = 10,000 J then the skier's height above ground would be:
mgh = 10,000
(56)(9.8)h = 10,000
h = 10,000/(56)(9.8) = 18.2 m <=
and with the KE of the skier added the total skier's ME = 17,168 J
which would come from a ski start hill of height = h:
where mgh = 17,168 J
h = 17,168/(9.8)(56) = 31.3 m <= max height of starting hill

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Your answer is exactly right. Don't let anyone tell you it's wrong.
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