If 161 g of water at 85'C is cooled to ice at 0'C, find the change in heat content of the system.

Need to solve this Calorimetry problem.

q = ms(change T)

q1 = (161 g)(4.184 J/g*C)(85)
q1 = 57258.04 Joules from 85 C to 0 C

At 0 C we have a phase change.

161 g x 1 mol/18.106 g = 8.94 mols H2O

q2 = (8.94 mols)(6.01 kJ/mol) = 53.7294 kJ

Add q1 and q2 (don't forget to convert q1 to kJ!)

57.25804 kJ + 53.7294 kJ = 111 kJ