Consider the reaction 2HBr t, H2 + Br2. If 0.5 M of HBr decomposes at 25OC, and
0.13 M of Br2 is formed when the reaction has reached equilibrium, what is the
equilibrium constant for this reaction
0.13 M of Br2 is formed when the reaction has reached equilibrium, what is the
equilibrium constant for this reaction
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2HBr<---------->H2 + Br2
0.5-2x x x
K =x2/(0.5-2x)^2 =(0.13)^2/0.5-0.26)^2 = 0.13^2/0.24^2 = 0,0169
0.5-2x x x
K =x2/(0.5-2x)^2 =(0.13)^2/0.5-0.26)^2 = 0.13^2/0.24^2 = 0,0169