What is the formula for acceleration?-something with velocity-a = F / m, where F is the force acting on the object and m is the mass of the object.
Average acceleration is the change in velocity divi
A Ferris wheel 20.0min diameter rotates once every 21.0s
What is the ratio of a persons apparent weight to her real weight at the top?(Wa / W)
What is the ratio of a persons apparent weight to her r
This is for a physics hw. I dont get it. I think the answer is gravity. Im not sure yet. Can someone deliver me from getting a zero please???!!-In this case weight is the force of gravity exerted betw
Determine the moment of inertia of a cylinder of radius 0.51 m, height 1.9 m and density (0.729 - 0.3645r + 0.371r^2) kg/m^3 about the center. Answer in units of kg*m^2.
I know I have to integrate u
If we take the special theory of relativity it hinges on only this postulate.
The speed of light is the same for any inertial observer anywhere.There is no absolute right frame of reference.
Everyth
the bob is attached to a very light ridiged rod of length L that is pivoted at the other end. the bullet is stopped in the bob. how high is the bob raised-initial KE = 0.5 m1 * V^2
moment of inertia M
In a hydraulic lift, the radii of the pistons are 2.65 cm and 9.2 cm. A car weighing W = 10.8 kN is to be lifted by the force of the large piston.
(a) What force Fa must be applied to the small piston
The shark has a mass of 2.04 x 10^4 kg. The blue whale has a mass of 1.81 x 10^5 kg. The distance between them is 1.5m. How large is the gravitational force between them? Show your work.
I got F=0.10
Please help! Easy 10 points best detailed answerwith work being shown.-average acceleration:a
△v: the rate of change(this time)16.0 m/s-2.0 m/s
△t: this time7.0s
a=△V/△t=(16.0 m/s-2.0 m/s)/7.0s=2 m/s
A uniform ladder of length 3.25m and weighing 250 N is placed against a smooth vertical wall with its lower end 1.25m from the wall.If coefficient of friction b/w ladder and floor is 0.3, then, find t
A 5 kg box slides down a long, frictionless
incline of angle 32. It starts from rest at time
t = 0 at the top of the incline at a height 20 m
above the ground. Find the potential energy of the box at
A 17.1 kg block is dragged over a rough, hor-
izontal surface by a constant force of 93.1 N
acting at an angle of angle 28.5 above the
horizontal. The block is displaced 77.2 m and
the coefficient of
A plastic sphere of mass 3.00x10^-15 kg is suspended between two horizontally oriented, charged plates. If the electric field between the plates is 6.25x10^4 N/C downwards, what is the charge on the s
please help with this question
http://img683.imageshack.us/img683/1170/img0842dg.jpg
regards-First step is to calculate the potential energy of Ball A where it is:
PE = mgz = 3 * 9.8 * 12 = 352.8