The electron interference pattern of the figure was made by shooting electrons with 50 {\rm keV} of kinetic energy through two slits spaced 1.0 {\rm \mu m} apart. The fringes were recorded on a detector 1.0 {\rm m} behind the slits.
What was the speed of the electrons? (The speed is large enough to justify using relativity, but for simplicity do this as a non-relativistic calculation.)
v= ____ m/s
The figure is greatly magnified. What was the actual spacing on the detector between adjacent bright fringes?
change y = ____ um (mu m)
What was the speed of the electrons? (The speed is large enough to justify using relativity, but for simplicity do this as a non-relativistic calculation.)
v= ____ m/s
The figure is greatly magnified. What was the actual spacing on the detector between adjacent bright fringes?
change y = ____ um (mu m)
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Can't make out the units in your question. Also, there is no diagram, though the question refers to one.
To get speed, change energy from eV to joules (multiply ev by 1.6 x 10^-19). You then equate the result to (1/2)mv^2 to find v.
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To get the spacing you do 2 stages:
1) Find the electron's deBroglie wavelength using wavelength = h/p (= h/mv)
2) You then use the standard double-slit interference formula to find y (see link).
To get speed, change energy from eV to joules (multiply ev by 1.6 x 10^-19). You then equate the result to (1/2)mv^2 to find v.
______________________________________…
To get the spacing you do 2 stages:
1) Find the electron's deBroglie wavelength using wavelength = h/p (= h/mv)
2) You then use the standard double-slit interference formula to find y (see link).