Find x if sin(x+36^) = cos x
Write your solution please
Write your solution please
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sin(x)cos(36°) + sin(36°)cos(x) = cos(x)
sin(x)cos(36°) = cos(x) (1 - sin(36°))
tan(x) = (1 - sin(36°)) / cos(36°)
x = arctan[(1 - sin(36°)) / cos(36°)]
x = 27° + n∙180°, n e Z
sin(x)cos(36°) = cos(x) (1 - sin(36°))
tan(x) = (1 - sin(36°)) / cos(36°)
x = arctan[(1 - sin(36°)) / cos(36°)]
x = 27° + n∙180°, n e Z
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nsolve(sin(x+36)=cos(x), {x})
x=27 approximately...easy to do with microsoft math - once I realized that you were saying degrees...
x=27 approximately...easy to do with microsoft math - once I realized that you were saying degrees...
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If this is calculus or what ever you call it, then i wanna die soon cuz ima be taking it later on in high school
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293
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293
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293
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293
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42
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So you solve it. Stop trying to get people to do your homework.
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I wish I knew, but this isn't a simple question, and I suck at math!
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It's so easy. Can you solve it??
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I think that question could be incorrect ?
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If it's easy, then why do you have to ask us?