Straightening out a few things about Thermite.

There seems to be some major inconsistencies about the ratio and enthalpy. Some websites claim you should always use 8:3, Iron: Aluminum. Some say 1:2, some the reverse. Some say that Iron(II, III) Oxide burns with an enthalpy thousands more than Iron(III) Oxide, and others say a few hundred Can an expert straighten this out for me? If I bought some tan and some black iron oxide mortar colour, is it Iron(II, III) Oxide, Iron(III) Oxide, Iron(II) Oxide, or different for each (tan or black).

Magnetic iron oxide. Fe3O4 is used. or a even mixture of FeO + Fe2O3 If you add these you get Fe3O4, on paper, but not magnetic! The reaction is 3 Fe3O4 + 8 Al --> 9 Fe + 4 Al2O3.
This is used as an instant welder, so you want lots of hot iron. The reaction is quite exothermic.
The ratio here is 3 to 8

Firstly, we cna do this on our own...we need to first look at the equation you're making...

A majority of iron oxide is Iron (iii) Oxide so, lets use that,

Fe2O3 + 2 Al -> Al2O3 + 2 Fe

we need to make the final product a total of 1 molar.
although since some elements need 2 moles, we must multiply by 2.

so for 1 mol of Al2O3 we need 1 mole of iron oxide and 2 mols of aluminum.

and therefore we'ed need 159.684 grams of iron oxide and
53.964 grams of aluminum

We make a total weight...and then we dived both parts.

total weight = 213.648 g

divide the amount of aluminum into the total mass...

53.962 / 213.648 x 100 = 25%

And by complement...the rest is 75%

so the ratio is

25% Aluminum
75% Iron(iii) oxide.