How to find the equivelance point of a compound when titrated with 2 M NaOH and given the Ka
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How to find the equivelance point of a compound when titrated with 2 M NaOH and given the Ka

[From: ] [author: ] [Date: 11-08-15] [Hit: ]
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(HPTX ) HPTX<---> H+ + PTX- the Ka is 1.2x10-9
(HMTN) HMTN<---> H* + MTN- the Ka is 7.3x10-4
if both compounds are titrated with 2M NaOH at what pH does the equivalence point occur for each compound?

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what is the volume of NaOH used because this determines the number of moles NaOH used in the titration. the equivalence point is the point where the moles H+ = moles OH-
without this, we can't find the equivalence point
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