I need help with Physics!!!
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I need help with Physics!!!

[From: ] [author: ] [Date: 11-10-18] [Hit: ]
8 * 18.62 = 912.http://www.ajdesigner.......
A 5 kg box slides down a long, frictionless
incline of angle 32. It starts from rest at time
t = 0 at the top of the incline at a height 20 m
above the ground. Find the potential energy of the box at
t = 1 s .
Answer in units of J

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The force that is accelerating the box will be the component of its weight parallel to the slope, which is given by

F = mg sin (theta) = 5 * 9.8 * sin (32) = 25.97 N

Its acceleration will then be a = F/m = 25.97/5 = 5.2 m/s/s

The distance it will travel in 1 second is given by d = ut + 1/2 a t^2

Since u = 0 the first term goes to 0. The second term is 1/2 * 5.2 * 1^2 = 2.6 m.

This is the distance travelled down the slope, so you'll need some trig to calculate the vertical distance travelled. It ends up being 2.6 sin 32 = 1.38 m.

Now, the object's potential energy is given by its height above the floor. It started at 20 and dropped 1.38 m, so it is now 20-1.38 = 18.62 m high

PE = mgh = 5 * 9.8 * 18.62 = 912.38 J

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You can solve this numerical problem by using the following that link:

http://www.ajdesigner.com/phppotentialen…
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