The number of tickets sold each day for an upcoming performance of Handel's Messiah is given by N(x) = -0.4x^2 + 11.2x + 12, where x is the number of days since the concert was first announced. When will daily ticket sales peak and how many tickets will be sold that day?
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N(x) = -0.4x^2 + 11.2x + 12
Find the derivative:
N'(x) = -0.8x + 11.2
Find x-values where this equals 0:
-0.8x + 11.2 = 0
0.8x = 11.2
x = 14
So, on day 14 ticket sales will peak. Plug this back into the original equation to see what sales will be that day:
N(14) = -0.4(14)^2 + 11.2(14) + 12
N(14) = -78.4 + 156.8 + 12
N(14) = 90.4
So, on day 14 when ticket sales are at the highest, they will sell about 90 or 91 tickets.
Find the derivative:
N'(x) = -0.8x + 11.2
Find x-values where this equals 0:
-0.8x + 11.2 = 0
0.8x = 11.2
x = 14
So, on day 14 ticket sales will peak. Plug this back into the original equation to see what sales will be that day:
N(14) = -0.4(14)^2 + 11.2(14) + 12
N(14) = -78.4 + 156.8 + 12
N(14) = 90.4
So, on day 14 when ticket sales are at the highest, they will sell about 90 or 91 tickets.
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N(x) = -0.4x² + 11.2x + 12
is a parabola that opens downward and its peak occurs at the axis of symmetry:
x = -b/2a = -11.2/2(-0.4) = 14
This mean that the peak occurs on the 14th day after announcement.
The number of tickets sold will be:
N(14) = -0.4(14)² + 11.2(14) + 12 = 90.4
is a parabola that opens downward and its peak occurs at the axis of symmetry:
x = -b/2a = -11.2/2(-0.4) = 14
This mean that the peak occurs on the 14th day after announcement.
The number of tickets sold will be:
N(14) = -0.4(14)² + 11.2(14) + 12 = 90.4
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i find it easiest to use part of the quadratic equation for this; specifically the -b/2a part
so you have x= -b/2a
x = -11.2 / 0.8
x = 14
now just sub in your x value and solve for N(x) !
so N(14) = -0.4(14^2) + 11.2(14) + 12 = 90.4 tickets!
so you have x= -b/2a
x = -11.2 / 0.8
x = 14
now just sub in your x value and solve for N(x) !
so N(14) = -0.4(14^2) + 11.2(14) + 12 = 90.4 tickets!