Write the equation of the line that passes through (2, 4) and (1, -3) in slope-intercept form please help :]
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y = mx + b
m = (-3 - 4) / (1 - 2) = -7 / -1 = 7
y = 4
x = 2
4 = 2*7 + b
4 = 14 + b
-10 = b
y = 7x - 10.
m = (-3 - 4) / (1 - 2) = -7 / -1 = 7
y = 4
x = 2
4 = 2*7 + b
4 = 14 + b
-10 = b
y = 7x - 10.
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First, find the slope using the formula: m = y2-y1 / x2-x1
m = -3 -4 / 1 - 2 = -7/-1 = 7
So, the slope is 7.
Now, use this with either point to put in the formula y = mx + b:
4 = 7(2) + b
4 = 14 + b
b = -10
So, we have our slope of 7 and our intercept of -10, so the solution is:
y = 7x - 10
m = -3 -4 / 1 - 2 = -7/-1 = 7
So, the slope is 7.
Now, use this with either point to put in the formula y = mx + b:
4 = 7(2) + b
4 = 14 + b
b = -10
So, we have our slope of 7 and our intercept of -10, so the solution is:
y = 7x - 10