factorise completely p+q-(3p^2)+(3q^2)
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Hi friend,
p + q - 3p^2 + 3q^2 =
p + q + 3(q^2-p^2) =
p + q + 3(q-p)(p+q) =
(p+q) (1 + 3(p-q) =
(p+q) (1 + 3p - 3q)
p + q - 3p^2 + 3q^2 =
p + q + 3(q^2-p^2) =
p + q + 3(q-p)(p+q) =
(p+q) (1 + 3(p-q) =
(p+q) (1 + 3p - 3q)
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p+q-(3p^2)+(3q^2)
= p - (3p^2) + q+(3q^2)
= p (1-3) + q ( 1-3)
= ( 1-3) (p+q)
= p - (3p^2) + q+(3q^2)
= p (1-3) + q ( 1-3)
= ( 1-3) (p+q)