A sequence is given by...

X1=1
Xn+1=Xn(p+Xn)

Where p is a constant (p=0)

A.) Fifs X2 in terms of p.
B.) Show that X3=1+3p+2p^2.

Given that X3=1
C.) Find the value of p.
D.) Write down the value of X2008.

I think you mean p not =0
A) Put n=1, so X2=X1(p+X1)=1(p+1)=p+1
B) Put n=2, X3=X2(p+X2)=(p+1)(2p+1)=1+3p+2p^2
C) 1+3p+2p^2=1=> 3p+2p^23=0 => p(3+2p)=0 => p=-3/2 since p not 0
D) X1=1,X2=-1/2,X3=1 so sequence now repeats and clearly X2008=-1/2 (even suffix)