use intergration by parts to solve: lnz/z^2
-
∫ ln z dz/z^2
Let u = ln z and dv = dz/z^2
then du = dz/z and v = -1/z
- ln z/z + ∫ dz/z^2 = - ln z/z - 1/z + C
BTW, the word is "integration", not "intergration".
Let u = ln z and dv = dz/z^2
then du = dz/z and v = -1/z
- ln z/z + ∫ dz/z^2 = - ln z/z - 1/z + C
BTW, the word is "integration", not "intergration".