Drops of rain fall perpendicular to the roof of a parked car during a rainstorm. The drops strike the roof wit
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Drops of rain fall perpendicular to the roof of a parked car during a rainstorm. The drops strike the roof wit

[From: ] [author: ] [Date: 11-10-17] [Hit: ]
075kg/s we have units also of kgm/s^2 and this product is the average force acting on the roof-Its inversely proportional to the amount of dirt on the roof of the car.-(11m/s)(..F=.......
Drops of rain fall perpendicular to the roof of a parked car during a rainstorm. The drops strike the roof with a speed of 11 m/s, and the mass of rain per second striking the roof is 0.075 kg/s.
(a) Assuming the drops come to rest after striking the roof, find the average force exerted by the rain on the roof.

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F = m a which has units of kgm/s^2

notice that if we multiply 11m/s x 0.075kg/s we have units also of kgm/s^2 and this product is the average force acting on the roof

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It's inversely proportional to the amount of dirt on the roof of the car.

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(11m/s)(.075kg/s)
.825kg*m/s^2=F
F=.825 N
1
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