A uniform rectangular 82.95 kg refrigerator with height h = 2.299 m and width w = 1.041 m is pushed at a constant velocity across a level floor. The refrigerator is pushed in the horizontal direction halfway between the floor and the top of the refrigerator and the refrigerator does not tip over while being pushed. What is the value the coefficient of kinetic friction between the refrigerator and the floor?
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(82.95 x 9.8) = normal force of 812.91N.
The refrigerator is being pushed right at the level of it CM.
Height of push above floor = (2.229/2) = 1.1145m.
The CM is (1.041/2) = 0.5205m. behind the leading edge of the bottom.
In order to rotate, it has to rotate around the leading edge.
(812.91 x 0.5205)/1.1145 = maximum appliable force of 379.65N. at 1/2 height.
Friction coefficient max. = (379.65/812.91) = 0.467.
The refrigerator is being pushed right at the level of it CM.
Height of push above floor = (2.229/2) = 1.1145m.
The CM is (1.041/2) = 0.5205m. behind the leading edge of the bottom.
In order to rotate, it has to rotate around the leading edge.
(812.91 x 0.5205)/1.1145 = maximum appliable force of 379.65N. at 1/2 height.
Friction coefficient max. = (379.65/812.91) = 0.467.
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Just an error, you had 2.229 instead of 2.299. That was it. I got it.
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