Genetics Problem Help Please

The allele for pea comb (P) in chickens is dominant to the allele for single comb (p), but the alleles for black (B) and white (B') feather color show incomplete dominance, BB' individuals having "blue" feathers. If birds heterozygous for both pairs of genes are mated, determine what proportion of the offspring are expected to be:

a. single-combed
b. blue-feathered
c. white-feathered
d. white-feathered and pea-combed
e. blue-feathered and single-combed

Thank you!

Nice Question.
PpBB' X PpBB'

a. single-combed


Pp X Pp gives 1/4 pp. So answer is 1/4

b. blue-feathered
BB' X BB' gives 1/2 BB'. So answer is 1/2


c. white-feathered

BB' X BB' gives 1/4 B'B'. So, answer is 1/4

d. white-feathered and pea-combed

Pp X Pp gives 3/4 pea combed and BB' X BB' gives 1/4 B'B'. So the answer is 3/4 X 1/4 = 3/16.

e. blue-feathered and single-combed
Pp X Pp gives 1/4 pp and BB' X BB' gives 1/2 BB'. So the answer is 1/8.