I'm confused. Any type of help will be great.
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The nth term (in absolute value) is (0.6)^(2n-1) / (2n-1)!.
Since we have an alternating series, the error after n terms is bounded above by the absolute value of the (n+1)th term:
So, we need (0.6)^(2n-1) / (2n-1)! < 0.0000001 = 10^(-7),
==> n = 5 (or higher), by inspection.
I hope this helps!
Since we have an alternating series, the error after n terms is bounded above by the absolute value of the (n+1)th term:
So, we need (0.6)^(2n-1) / (2n-1)! < 0.0000001 = 10^(-7),
==> n = 5 (or higher), by inspection.
I hope this helps!