Could anybody help me with this problem? Deals with Rydberg equation.
Favorites|Homepage
Subscriptions | sitemap
HOME > > Could anybody help me with this problem? Deals with Rydberg equation.

Could anybody help me with this problem? Deals with Rydberg equation.

[From: ] [author: ] [Date: 12-11-06] [Hit: ]
-Evaluate the two terms in the parentheses (1/n2^2 - 1/n1^2) at the specified values.As n2 approaches infinity, 1/n2^2 approaches zero; therefore, at infinity we can consider this term to be equal to zero.For n1 = 1, n1^2 = 1,......
Using the Rydberg equation (delta E = RH(1/n2^2 - 1/n1^2) ), show that the energy of the transition from the lowest state (n1=1) to the highest energy state (n2=infinity) is given by delta E (kJ/mol) = -RH. Therefore, the magnitude of this constant is equal to the ionization energy of one mole of hydrogen atoms, in units of kJ/mol. How do I go about doing this?

-
Evaluate the two terms in the parentheses (1/n2^2 - 1/n1^2) at the specified values.

(A) 1/n2^2

As n2 approaches infinity, 1/n2^2 approaches zero; therefore, at infinity we can consider this term to be equal to zero.

(B) 1/n1^2

For n1 = 1, n1^2 = 1, and therefore 1/n1^1 = 1

Substitute these values in the original equation and simplfy:

delta E = RH(1/n2^2 - 1/n1^2) = RH(0 - 1) = -RH
1
keywords: with,anybody,Rydberg,this,equation,problem,Could,me,Deals,help,Could anybody help me with this problem? Deals with Rydberg equation.
New
Hot
© 2008-2010 http://www.science-mathematics.com . Program by zplan cms. Theme by wukong .