Pre-algebra question? HARD

Witches and black cats filled the sky; the jack0lattern counted 25 heads and 74 legs, how many many witches were flying How many cats?

Let x = number of witches
Let y = number of black cats

x+y=25 Both witches and cats have 1 head

2x + 4y = 74
Witches have 2 legs and
Black Kitty Cats have 4 legs

I'll use elimination method

-2x - 2y = -50
2x + 4y = 74
▬▬▬▬▬▬
..0 + 2y = 24

so y = 12

and
since
x+y = 25

we have

x+12 = 25

x = 25 - 12 = 13

Thus we have 13 witches
and 12 black cats {meeoww}

This isn't a legitimate question, you have no way of knowing how many of each there are because witches and cats both have heads and both have legs therefore you can't determine the answer.

Just condense it to a ratio of heads to legs, because you know cats have 4 legs and witches have only 2. There will be 12 cats and 13 witches. Hope it helped! :)

Sorry bro, i'm taking Pre-Algebra to but we haven't gotten that far........

13 witches and 12 cats