Can i reduce "(log4) / 12" ?
I want to know if this is this same as "(log1) / 3" OR if there is a way to reduce it even more please
I want to know if this is this same as "(log1) / 3" OR if there is a way to reduce it even more please
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You actually can't simplify it to log(1)/3
(log4) / 12
= log(2^2) / 12
= 2*log(2) / 12
= log(2) / 6
I think that's the most you can do
(log4) / 12
= log(2^2) / 12
= 2*log(2) / 12
= log(2) / 6
I think that's the most you can do
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Not much can be said unless we know what base has been used for log and also if there is any mistake in putting parentheses.
If "(log4) / 12" means:
A. {log₂(4)}/12" = 2/12 = 1/6
or
B. log{4/12) to any base = log(1/3) = - log 3
If "(log4) / 12" means:
A. {log₂(4)}/12" = 2/12 = 1/6
or
B. log{4/12) to any base = log(1/3) = - log 3
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What base is the log? 10, natural, some other base?