Cannonball muzzle velocity
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Cannonball muzzle velocity

[From: ] [author: ] [Date: 12-11-06] [Hit: ]
(and the horizontal angle was arctan(18.8/77) = 13.......
If you shoot a cannonball horizontally and at its apex of 18 meters it is traveling 77 m/s, what was its muzzle velocity? (It weighs 4.2 kg). Thanks!

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If it is shot horizontally it won't rise to a height of 18m.

So I'll ignore the horizontal bit.

Let Initial vertical velocity component be Vyi

so Viy^2 = 2gh = 2*9.8*18 = 352.8 m^2/s^2
Viy = sqrt(352.8) = 18.8 m/s

At the apex, Vy = 0, so v = Vx = 77 m/s

So the muzzle velocity was

v = sqrt(Vx^2 + Viy^2) = 79.3 m/s

(and the "horizontal" angle was arctan(18.8/77) = 13.7 deg :)
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