A golf ball with mass 45.90 g and diameter 42.60 mm is struck such that it is moving with a speed of 53.47 m/s and rotating at with an angular frequency of 2711 rpm. What is the kinetic energy of the golf ball?
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Hi Holmes, the kinetic energy is sum of two
One is linear got by 1/2 m v^2
The other is rotational kinetic energy 1/2 I w^2
Here I = m r^2 /2
and w = 2711 * 2pi/ 60 rad/s
m is given change into kg
dia is given therefrom you can get r. change it into meter
v = 53.47 m/s
Hope you would plug and find the required by yourself
All the best dear
One is linear got by 1/2 m v^2
The other is rotational kinetic energy 1/2 I w^2
Here I = m r^2 /2
and w = 2711 * 2pi/ 60 rad/s
m is given change into kg
dia is given therefrom you can get r. change it into meter
v = 53.47 m/s
Hope you would plug and find the required by yourself
All the best dear