400 kg of N2 is mixed with 200 kg of H2 to produce 220 kg of NH3. Calculate the percentage yield of ammonia.
The equation is 2 N2 + 3 H2 = 2 NH3
Someone please help me figure this out!!!
The equation is 2 N2 + 3 H2 = 2 NH3
Someone please help me figure this out!!!
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First solve for the theoretical yield of products based on the given amount of BOTH reactants. The lower number will be the limiting reactant. For 400kg N2, I found that 243.2 kg of NH3 should be made. For 200kg H2, I found that 1125.9kg of NH3 should be made. Clearly N2 is the limiting reactant. Your actual yield is 220kg NH3 as stated. The percent yield is simply (actual yield / theoretical yield * 100). Thus, (220/243.2*100) = 90.5%
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