Quantitative Chemistry, Help!!
Favorites|Homepage
Subscriptions | sitemap
HOME > > Quantitative Chemistry, Help!!

Quantitative Chemistry, Help!!

[From: ] [author: ] [Date: 12-10-31] [Hit: ]
-First solve for the theoretical yield of products based on the given amount of BOTH reactants. The lower number will be the limiting reactant. For 400kg N2, I found that 243.2 kg of NH3 should be made. For 200kg H2,......
400 kg of N2 is mixed with 200 kg of H2 to produce 220 kg of NH3. Calculate the percentage yield of ammonia.
The equation is 2 N2 + 3 H2 = 2 NH3
Someone please help me figure this out!!!

-
First solve for the theoretical yield of products based on the given amount of BOTH reactants. The lower number will be the limiting reactant. For 400kg N2, I found that 243.2 kg of NH3 should be made. For 200kg H2, I found that 1125.9kg of NH3 should be made. Clearly N2 is the limiting reactant. Your actual yield is 220kg NH3 as stated. The percent yield is simply (actual yield / theoretical yield * 100). Thus, (220/243.2*100) = 90.5%

-
5
1
keywords: Quantitative,Help,Chemistry,Quantitative Chemistry, Help!!
New
Hot
© 2008-2010 http://www.science-mathematics.com . Program by zplan cms. Theme by wukong .