Need help with physics problem about tarzan jumping from a cliff
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Need help with physics problem about tarzan jumping from a cliff

[From: ] [author: ] [Date: 12-10-31] [Hit: ]
c)a = F/m = 307.18/(820/g) = 3.......
Question 1 (20 points) Tarzan, who weights 820 N, swings from a cliff at the end of a 20 m vine
that hangs from a high tree limb and initially makes an angle of 22o with the vertical.
Immediately after Tarzan steps off the cliff, the tension in the vine is 760 N.

b. What is the net force (magnitude and direction) on Tarzan at that moment?

c. What is Tarzan’s acceleration (magnitude and direction) just then?

i did part a im just really really confused on these last two parts any help would be great thank you ten points

-
Fy = 760cos22° - 820 = -115.34 N
Fx = 760sin22° = 284.7 N

b)
Ftot = √[Fx²+Fy²] = 307.18 N
Θ = arctan[115.34/284.7] = 22° below horizontal

c) a = F/m = 307.18/(820/g) = 3.67 m/s² @ 22° below horizontal
1
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