PLEASE I don't understand, I answered this question but I did it wrong and I need to know how to do it right and get the right answer.
Determine without graphing, whether the function G(x)=2x^4+3x^3 is even,odd, or neither?
show step by step
Determine without graphing, whether the function G(x)=2x^4+3x^3 is even,odd, or neither?
show step by step
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Test for even symmetry: Make the x negative.
g(-x) = 2(-x)^4 + 3(-x)^3
Simplify
g(-x) = 2x^4 - 3x^3
Is this the same as the original equation? No. Then it doesn't have even symmetry.
Test for odd: Make the outside of the brackets negative.
g-(x) = -(2x^4 + 3x^3)
Simplify
g-(x) = -2x^4 - 3x^3
Is this the same as the even test? No. The equation does not have odd symmetry.
The equation has no symmetry.
g(-x) = 2(-x)^4 + 3(-x)^3
Simplify
g(-x) = 2x^4 - 3x^3
Is this the same as the original equation? No. Then it doesn't have even symmetry.
Test for odd: Make the outside of the brackets negative.
g-(x) = -(2x^4 + 3x^3)
Simplify
g-(x) = -2x^4 - 3x^3
Is this the same as the even test? No. The equation does not have odd symmetry.
The equation has no symmetry.
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G(x)=2x^4+3x^3
G(-x) = 2x^4-3x^3
Neither
G(-x) = 2x^4-3x^3
Neither