It takes you 8.3 min to walk with an average
velocity of 1.4 m/s to the north from the bus
stop to the museum entrance.
How far did you walk?
Answer in units of m
What is your direction?
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A car traveling in a straight line has a velocity
of 6.85 m/s at some instant. After 3.68 s, its
velocity is 12.5 m/s.
What is its average acceleration in this time
interval?
Answer in units of m/s^2?
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With an average acceleration of −1.9 m/s
2
,
how long will it take a cyclist to bring a bicycle
with an initial speed of 14.9 m/s to a complete
stop?
Answer in units of s
velocity of 1.4 m/s to the north from the bus
stop to the museum entrance.
How far did you walk?
Answer in units of m
What is your direction?
---------------------------
A car traveling in a straight line has a velocity
of 6.85 m/s at some instant. After 3.68 s, its
velocity is 12.5 m/s.
What is its average acceleration in this time
interval?
Answer in units of m/s^2?
--------------------------------------…
With an average acceleration of −1.9 m/s
2
,
how long will it take a cyclist to bring a bicycle
with an initial speed of 14.9 m/s to a complete
stop?
Answer in units of s
-
1. a) Make velocity in terms of meters per minute
60 seconds in a minute so 1.4 m/s * 60 = 84 meters per minute
84 m/min x 8.3 = 697.2 meters
b) Not sure what it means. I assume it means north?
2. a = (vf-v0)/t = (12.5 m/s - 6.85 m/s)/3.68 s = 1.53 m/s^2
3. I think this is right -1.9 m/s^2 = (-14.9 m/s)/t Then solve for t
t = (-14.9 m/s)/(-1.9 m/s^2) = 7.842 s
60 seconds in a minute so 1.4 m/s * 60 = 84 meters per minute
84 m/min x 8.3 = 697.2 meters
b) Not sure what it means. I assume it means north?
2. a = (vf-v0)/t = (12.5 m/s - 6.85 m/s)/3.68 s = 1.53 m/s^2
3. I think this is right -1.9 m/s^2 = (-14.9 m/s)/t Then solve for t
t = (-14.9 m/s)/(-1.9 m/s^2) = 7.842 s