I need help with this problem:
There is an E-field in a region of space, and a +50.0 nC charge is placed at a point where the potential is 470 V. When released the charge moves, while the field does 235.0 µJ of work on it. What is the potential of the final location of the charge?
? V
So I figured that I can use deltaV=Ed to find Vfinal. But I have to find d first, which is what I can't figure out. Do I use E = k q/r^2 to do that? But then I need E?? Help!! Thanks!
There is an E-field in a region of space, and a +50.0 nC charge is placed at a point where the potential is 470 V. When released the charge moves, while the field does 235.0 µJ of work on it. What is the potential of the final location of the charge?
? V
So I figured that I can use deltaV=Ed to find Vfinal. But I have to find d first, which is what I can't figure out. Do I use E = k q/r^2 to do that? But then I need E?? Help!! Thanks!
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BY ∆W = -q∆V [-ve as work is done on the charge]
=>235 x 10^-6 = -50 x 10^-9 x ∆V
=>∆V = -4700 Volt
Thus by V2 - V1 = -∆V
=>V2 = -∆V + V1
=>V2 = -4700 + 470
=>V2 = -4230 Volt
=>235 x 10^-6 = -50 x 10^-9 x ∆V
=>∆V = -4700 Volt
Thus by V2 - V1 = -∆V
=>V2 = -∆V + V1
=>V2 = -4700 + 470
=>V2 = -4230 Volt
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work done by the field = - q deltaV so 235 x 10^-6 J = - 50.0 x 10^-9 deltaV solve for deltaV (negative since the potential goes down)
deltaV = Vf - Vi = Vf - 470 solve for Vf (I got -4230 V)
deltaV = Vf - Vi = Vf - 470 solve for Vf (I got -4230 V)