I chose C as my answer. Is that correct?
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Answer is D :
Since both charges are positive, the charge's individual electric fields oppose and therefore subtract in the area between them. To the left or to the right of either charge, their fields point in the same direction and add.
E = kq1/r^2 - kq2/(2r)^2
q1 = q2 => E = kq[1/r^2 - 1/4r^2] = 3kq/4r^2 so the answer is D
Since both charges are positive, the charge's individual electric fields oppose and therefore subtract in the area between them. To the left or to the right of either charge, their fields point in the same direction and add.
E = kq1/r^2 - kq2/(2r)^2
q1 = q2 => E = kq[1/r^2 - 1/4r^2] = 3kq/4r^2 so the answer is D
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E is the correct answer:
(Positive field is toward the right.)
Field from charge on the right = -kq/(2r)² = -kq/4r²
Field from charge on the left = +kq/r²
The sum is (kq/r²)*(1 - 1/4) = 3kq/(4r²)
(Positive field is toward the right.)
Field from charge on the right = -kq/(2r)² = -kq/4r²
Field from charge on the left = +kq/r²
The sum is (kq/r²)*(1 - 1/4) = 3kq/(4r²)