A bowler throws a 1.6 kg ball down a 19.2 m lane. Th ball is traveling at 9.7 m/s when it is released. If the kinetic friction coefficient is .09, how fast is the ball moving when it hits the pins?
Given:
m = 1.6 kg
d = 19.2 m
Fk coefficient = .09
initial velocity = 9.7 m/s
final velocity = ?
acceleration = ?
And this is what I've done (I'm not sure if it's correct):
Fg = (1.6)(-9.8) = -15.68
Fn (normal force) = 15.68
Fk = (15.68)(.09) = 1.4
Fnet = 1.6a
I am completely stuck. I need to find the acceleration so I can plug in values to one of the basic kinematic equations, but I don't know how to find the acceleration. Help please!!!
Given:
m = 1.6 kg
d = 19.2 m
Fk coefficient = .09
initial velocity = 9.7 m/s
final velocity = ?
acceleration = ?
And this is what I've done (I'm not sure if it's correct):
Fg = (1.6)(-9.8) = -15.68
Fn (normal force) = 15.68
Fk = (15.68)(.09) = 1.4
Fnet = 1.6a
I am completely stuck. I need to find the acceleration so I can plug in values to one of the basic kinematic equations, but I don't know how to find the acceleration. Help please!!!
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Sum the forces along your x axis. Σf = ma
If your frame of reference has an origin at the beginning of the lane, Σf = -1.4N, or just the kinetic friction force.
-1.4N = 1.6 kg * a
a = -1.4N / 1.6kg
a = -.875 m/ss
You can insert that acceleration in your other kinematic equations to solve for Vf.
If your frame of reference has an origin at the beginning of the lane, Σf = -1.4N, or just the kinetic friction force.
-1.4N = 1.6 kg * a
a = -1.4N / 1.6kg
a = -.875 m/ss
You can insert that acceleration in your other kinematic equations to solve for Vf.
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if the ball is going downward the force of gravity should be working on it and pulling it down 9.8 meters per second which would be the acceleration