I have tried over and over again on these problems--to no avail. Please help me out, as I will award points for answers that are correct.
A car can decelerate at -4.40 m/s2 without skidding when coming to rest on a level road. What would be the magnitude of its deceleration if the road were inclined at 14° uphill? Assume the same static friction coefficient.
Previous Answers: -6.77, -2.03, 3.71, and 6.8
As the snow begins to melt, the coefficient of static friction decreases and the snow eventually slips. Assuming that the distance from the chunk to the edge of the roof is 5.6 m and the coefficient of kinetic friction is 0.20, calculate the speed of the snow chunk when it slides off the roof.
Previous Answers: 5.31 and 7.36
If the edge of the roof is 11.0 m above ground, what is the speed of the snow when it hits the ground?
No answers attempted.
Please help me out!
A car can decelerate at -4.40 m/s2 without skidding when coming to rest on a level road. What would be the magnitude of its deceleration if the road were inclined at 14° uphill? Assume the same static friction coefficient.
Previous Answers: -6.77, -2.03, 3.71, and 6.8
As the snow begins to melt, the coefficient of static friction decreases and the snow eventually slips. Assuming that the distance from the chunk to the edge of the roof is 5.6 m and the coefficient of kinetic friction is 0.20, calculate the speed of the snow chunk when it slides off the roof.
Previous Answers: 5.31 and 7.36
If the edge of the roof is 11.0 m above ground, what is the speed of the snow when it hits the ground?
No answers attempted.
Please help me out!
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a) a = -4.40 - g*sin14° = -6.77 m/s²
b)
1) The formula is V1 = √[2*a*x] where a = g*(sinΘ - µcosΘ) and x is the distance along the slope of the roof. Without any info on the slope, no answer is possible.
2) If the vertical height of the eave is h, then V = √(V1² + 2gh). Once again, without V1, no answer.
b)
1) The formula is V1 = √[2*a*x] where a = g*(sinΘ - µcosΘ) and x is the distance along the slope of the roof. Without any info on the slope, no answer is possible.
2) If the vertical height of the eave is h, then V = √(V1² + 2gh). Once again, without V1, no answer.