The force required to stretch a Hooke’s-law spring varies from 0 N to 53.6 N as we stretch...

part 1)
The force required to stretch a Hooke’s-law
spring varies from 0 N to 53.6 N as we stretch
the spring by moving one end 12 cm from its
unstressed position.
Find the force constant of the spring.
Answer in units of N/m


part 2)
Find the work done in stretching the spring.
Answer in units of J

1) k = F/x = 53.6/.12 = 446.67 N/m

2) W = ½F*x = .5*53.6*.12 = 3.22 J