I'm so confused with this..
Can you help?
What is the normal force acting on a 8kg mass which is being pulled at a constant velocity of 7 m/sec by a rope having a tension of 45 newtons at an angle of 41 degrees to the horizontal?
Can you help?
What is the normal force acting on a 8kg mass which is being pulled at a constant velocity of 7 m/sec by a rope having a tension of 45 newtons at an angle of 41 degrees to the horizontal?
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Hello:
The best way to approach this problem is by creating a Free-Body diagram. In this type of Physics problems where forces are involved this is the best way to always approach for it helps you visualize what's given to you in the problem. But enough said, let's get to the answer.
the block has a mass of 8 Kg. at this point we can assign our first normal for and we're going to call it N_1. N_1 will point upwards and will have a positive sign convention. N_1= Mass*Gravitational Acceleration = 8*9.81= 78.48 N. This would be our answer if this block was not moving at a constant speed of 7 m/s. In that case we have to add the the y-component of the tension in that rope to our N_1 initial Normal force.
We set a triangle depicting the hypotenuse as the 45 N, the vertical y-component, and the horizontal x-component. in order to get the y-comp. We will set it as follow:
y-component = 45N*sin(41) = 29.523N
Finally our total Normal force will be:
N = N_1 + y_component = 78.48N+29.523N
N = 108.003N
I hope this helps.
The best way to approach this problem is by creating a Free-Body diagram. In this type of Physics problems where forces are involved this is the best way to always approach for it helps you visualize what's given to you in the problem. But enough said, let's get to the answer.
the block has a mass of 8 Kg. at this point we can assign our first normal for and we're going to call it N_1. N_1 will point upwards and will have a positive sign convention. N_1= Mass*Gravitational Acceleration = 8*9.81= 78.48 N. This would be our answer if this block was not moving at a constant speed of 7 m/s. In that case we have to add the the y-component of the tension in that rope to our N_1 initial Normal force.
We set a triangle depicting the hypotenuse as the 45 N, the vertical y-component, and the horizontal x-component. in order to get the y-comp. We will set it as follow:
y-component = 45N*sin(41) = 29.523N
Finally our total Normal force will be:
N = N_1 + y_component = 78.48N+29.523N
N = 108.003N
I hope this helps.