PLEASE HELP! How do you prepare 100mL of 1.00 mol/L soduim hydroxide

What's the procedure? I have no idea how to figure this out! :C All I can figure out is the molar mass of NaOH... It's 39.998 g/mol.

Make it a two-step procedure. You only need two basic formulas C = n / V, and n = m / M

You have a volume and a concentration

use C = n / V. rearrange it to get n = C x V,

n = 1.00mol / L x 0.100 L = 0.100 mol of NaOH

Mass of NaOH. Use n = m / M. Rearrange the formula to get mass = n x M

Mass of NaOH = 0.100 mol x 39.998 = 3.9998 g

So get a 100 mL volumetric flask. Add 3.9998 g of NaOH to it. Add about 50 mL of distilled water to the flask. Stir the contents until the NaOH dissolves completely, then fill the flask up to the "scratch" line. Stopper it. inverte it 2 or 3 times and there y ou go.

39.998 g/mol x 1.00 mol / 1000 mL x 100 mL
dissolve that amount into 100 mL of water.