A bullet of mass 20 gram travelling with a velocity of 16m/s penetrates a sand bag and is brought to rest in 0.05 seconds.Find the depth of penetration and average retarding force of the sand.
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Impulse = Force . time = change of momentum
F . 0.05 = 16 . 0.020
F = 6.4 N
a = F/m = 6.4 / 0.02 = 320 m/s/s
d = v^2 / 2 . a = 16^2 / 2 . 320 = 16 / 2 . 20 = 0.4 m
F . 0.05 = 16 . 0.020
F = 6.4 N
a = F/m = 6.4 / 0.02 = 320 m/s/s
d = v^2 / 2 . a = 16^2 / 2 . 320 = 16 / 2 . 20 = 0.4 m