In a college parking lot, the number of ordinary cars is larger than the number of sport utility vehicles by 77.3%. The difference between the number of cars and the number of SUVs is 17. Find the number of SUVs in the lot.
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looks like some algebra
you see the difference
let O be the number of ordinary cars
let S be the number of SUV
O - S = 17
we also know that the percentage of ordinary cars is 77.3 larger than sport utility vehicles
this means that if there is 1 SUV there are 1.773 ordinary cars
so the equation for this is
O/S = 1 + 0.773
now you solve for O in one of the equations and put it in the other and then solve for S in the other equation
O = S*1.773
put in equation one
O - S = 17
S*1.773 - S = 17
S*(1.773-1) = 17
S *(0.773) = 17
S = 17/0.773
S = 21.9
rounding off means
S = 22 Suv's in the lot
you can solve for the value of ordinary vehicles by putting back into either equation one or the equation 2
O - S = 17
and S - 22
then
O = 22+ 17 = 39
to check percentage
39/22 = 1.7727272727272727272727272727273
once rounded the answer is the same as the question
you see the difference
let O be the number of ordinary cars
let S be the number of SUV
O - S = 17
we also know that the percentage of ordinary cars is 77.3 larger than sport utility vehicles
this means that if there is 1 SUV there are 1.773 ordinary cars
so the equation for this is
O/S = 1 + 0.773
now you solve for O in one of the equations and put it in the other and then solve for S in the other equation
O = S*1.773
put in equation one
O - S = 17
S*1.773 - S = 17
S*(1.773-1) = 17
S *(0.773) = 17
S = 17/0.773
S = 21.9
rounding off means
S = 22 Suv's in the lot
you can solve for the value of ordinary vehicles by putting back into either equation one or the equation 2
O - S = 17
and S - 22
then
O = 22+ 17 = 39
to check percentage
39/22 = 1.7727272727272727272727272727273
once rounded the answer is the same as the question
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C = 1.773*S
C - S = 17
Solving simultaneously,
S = 22
C = 39
C - S = 17
Solving simultaneously,
S = 22
C = 39