Can you show me how you solve this?
A vector has a magnitude of 3.5m and points in a direction that is 140 degrees counterclockwise from the X axis.
Find the X components of this vector.
A vector has a magnitude of 3.5m and points in a direction that is 140 degrees counterclockwise from the X axis.
Find the X components of this vector.
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the counter clock wise direction is taken as positive....ie 140 degree is the angle with positive X axis..
so the component along X will be 3.5cos140m=-2.68115m(note the negative sign)
the angle with positive y axis is 50 degrees...so Y component is 3.5cos50=2.25m
so the component along X will be 3.5cos140m=-2.68115m(note the negative sign)
the angle with positive y axis is 50 degrees...so Y component is 3.5cos50=2.25m
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(180 - 140) = 40 degree angle to x axis.
(cos 40) x 3.5 = 2.681m. along x axis, and
(sin 40) x 3.5 = 2.25m. along y axis.
If you need + and - answers, I suppose it's 2.681m. -x, and 2.25m. +y.
(cos 40) x 3.5 = 2.681m. along x axis, and
(sin 40) x 3.5 = 2.25m. along y axis.
If you need + and - answers, I suppose it's 2.681m. -x, and 2.25m. +y.
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x_component = 3.5 * cos(140) = - 2.6812
y_component = 3.5 * sin(140) = 2.25
y_component = 3.5 * sin(140) = 2.25