How do i do these problems? (math)

i have like 50 problems to do and had a question on some

how do i factor this expression? (3x-2)^-4 (x+3)+(x+3)^2(3x-2)^-3

simplify these fractions: ((1/x)+1)/(1/x) and 3x/(3x+y)

solve these equations: ((4x)/(x^3+3))-1=0
xy-z=z+wx-3x
(2x-1)^2(x-5)^2+(2x-1)^3(x-5)=0

and exponent rules, which are true? (how do i know)
e^(2ln 2 - ln 5) = 4/5

please help me with as much as you can

I'll do couple.
(3x-2)^-4 =1/(3x-2)^4
rewrite it
(x+3) + (x+3)²
-------- + ------
(3x-2)^4,,,,(3x-2)³
you have the commondeminator= (3x-2)^4
top
[(x+3) +(x+3)²(3x-2)] / (3x-2)^4
factor out (one (x+3)
top
(x+3)[ 1+(x+3)(3x-2)]/ (3x-2)^4

the problem,
((1/x)+1)/(1/x)
you find CMD for the top,
and when you have A/B / C/D = A/B * D/C
just flip the bottom and multiply them