Find the distance traveled
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Find the distance traveled

[From: ] [author: ] [Date: 11-06-28] [Hit: ]
acc = 0.3 *9.81 = 2.0 = 25^2 - 2* 2.s = 106.note: acc is actually deceleration as a result of friction; thus negative value-Youd need to know the mass or weight of the box in order to answer this question.......
A box is moving with an initial velocity v = 25 m/s. If the coefficient of kinetic friction between the floor and the box is μ = 0.3 how far will the box travel before coming to rest?

Please explain or provide the equations you used if possible! Thanks!

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let mass be m
friction = mg * 0.3
= m * acc
acc = 0.3 *9.81 = 2.943m/s2

u=25; v=0
v2 = u2 + 2as
0 = 25^2 - 2* 2.943 *s
s = 106.18 m
answer
note: acc is actually deceleration as a result of friction; thus negative value

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You'd need to know the mass or weight of the box in order to answer this question.
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