Zoltan supports a 5m long 10kg beam at one end. The beam is uniform in cross section and in density, and is supported at the other end by a bench.
Q: What force must Zoltan exert in order to keep the beam horizontal? Justify your answer.
I know that a rigid body in static equilibrium requires there to be no net force applied to the body... does that just mean that this Zoltan bloke will therefore be exerting no force on the beam? If not, would it then just be half of the force due to gravity from the beam on both good old Zoltan and the bench? (ie. 1/2 (10kg x 9.81m/s/s) = 49.05N) or is that completely wrong haha
Q: What force must Zoltan exert in order to keep the beam horizontal? Justify your answer.
I know that a rigid body in static equilibrium requires there to be no net force applied to the body... does that just mean that this Zoltan bloke will therefore be exerting no force on the beam? If not, would it then just be half of the force due to gravity from the beam on both good old Zoltan and the bench? (ie. 1/2 (10kg x 9.81m/s/s) = 49.05N) or is that completely wrong haha
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You're exactly right -- Zoltan has to support 1/2 of the mass of the beam. Gravity is exerting 98.1N in the downward direction, the bench is exerting 49.05N in the upward direction, and out pal Zoltan is exerting the other 49.05N in the upward direction to keep the beam in both translational and rotational equilibrium.