A container is filled with fluid 1, and the apparent depth of the fluid is 5.00 cm. The container is next filled with fluid 2, and the apparent depth of this fluid is 4.00 cm. If the index of refraction of the first fluid is 1.60, what is the index of refraction of the second fluid?
I know the answer is supposed to be 2.00 but can someone show me step by step how to solve this. Thanks for your help I appreciate it.
I know the answer is supposed to be 2.00 but can someone show me step by step how to solve this. Thanks for your help I appreciate it.
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Actual depth = Apparent depth x refractive index
Actual depth = 5 x 1.6 = 8 cm
Actual depth = 4 x (μ) = 8
μ = 2
Actual depth = 5 x 1.6 = 8 cm
Actual depth = 4 x (μ) = 8
μ = 2